描述
104. 二叉树的最大深度 - 力扣(Leetcode)
分析
实现
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| import java.lang.Math; import java.util.Queue; import java.util.LinkedList;
public class MaximumDepthOfBinaryTree104 { public static void main(String[] args){ Integer[] arr = {3,9,20,null,null,15,7}; TreeNode root = MyUtils.buildTree(arr); System.out.println(new Solution().maxDepth(root)); } }
class Solution { public int maxDepth1(TreeNode root) { if(root == null){ return 0; } int leftDepth = maxDepth(root.left); int rightDepth = maxDepth(root.right); return Math.max(leftDepth, rightDepth) + 1; } public int maxDepth2(TreeNode root) { if (root == null) { return 0; } Queue<TreeNode> que = new LinkedList<>(); que.offer(root); int res = 0, size = 0; while(!que.isEmpty()){ size = que.size(); res++; TreeNode temp;
for(int i = 0; i < size; i++){ temp = que.poll(); if(temp.left != null) que.offer(temp.left); if(temp.right != null) que.offer(temp.right); } } return res; } public int maxDepth3(Node root) { if(root == null){ return 0; } int depth = 0; if (root.children != null) { for (Node child : root.children) { depth = Math.max(depth,maxDepth(child)); } } return depth + 1; } public int maxDepth4(Node root){ if (root == null) { return 0; } Queue<Node> que = new LinkedList<>(); int depth = 0, size = 0; que.offer(root); while(!que.isEmpty()){ size = que.size(); depth++; Node temp; for (int i = 0; i < size; i++) { temp = que.poll(); if (temp.children != null) { for (Node child : temp.children) { if (child != null) { que.offer(child); } } } } }
return depth; } }
class TreeNode { int val; TreeNode left; TreeNode right;
public TreeNode(){}; public TreeNode(int val){this.val = val;} public TreeNode(int val, TreeNode left, TreeNode right){ this.val = val; this.left = left; this.right = right; } }
class MyUtils {
public static TreeNode buildTree(Integer[] arr) { return buildTreeHelper(arr, 0); }
public static TreeNode buildTreeHelper(Integer[] arr, Integer index) { if (index >= arr.length || arr[index] == null) { return null; }
TreeNode node = new TreeNode(arr[index]);
node.left = buildTreeHelper(arr, 2 * index + 1); node.right = buildTreeHelper(arr, 2 * index + 2);
return node; }
public static void levelOrderTraversal(TreeNode root) { if (root == null) { return; }
Queue<TreeNode> queue = new LinkedList<>(); queue.add(root);
while (!queue.isEmpty()) { TreeNode node = queue.poll(); System.out.print(node.val + " ");
if (node.left != null) { queue.add(node.left); }
if (node.right != null) { queue.add(node.right); } } } }
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总结