描述
257. 二叉树的所有路径 - 力扣(Leetcode)
分析
实现
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| import java.util.ArrayList; import java.util.Stack; import java.util.List;
public class BinaryTreePaths257 { public static void main(String[] args){ TreeNode root = MyUtils.buildTree(new Integer[]{1,2,3,null,5}); for (String s : new Solution().binaryTreePaths(root)) { System.out.println(s); } } }
class Solution { public List<String> binaryTreePaths1(TreeNode root) { List<String> res = new ArrayList<>(); if (root == null) { return res; } List<Integer> paths = new ArrayList<>(); traversal(root, paths, res); return res; } void traversal(TreeNode node,List<Integer> paths, List<String> res){ paths.add(node.val); if (node.left == null && node.right == null) { StringBuilder temp = new StringBuilder(); for (int i = 0; i < paths.size() - 1; i++) { temp.append(paths.get(i) + "->"); } temp.append(paths.get(paths.size() - 1)); res.add(temp.toString()); return; } if(node.left != null){ traversal(node.left,paths,res); paths.remove(paths.size() - 1); } if(node.right != null){ traversal(node.right,paths,res); paths.remove(paths.size() - 1); } }
public List<String> binaryTreePaths(TreeNode root) { List<String> res = new ArrayList<>(); if (root == null) { return res; } Stack<Object> stack = new Stack<>(); stack.push(root); stack.push(root.val + ""); String path; TreeNode tempNode; while(!stack.isEmpty()){ path = (String)stack.pop(); tempNode = (TreeNode)stack.pop(); if (tempNode.left == null && tempNode.right == null) { res.add(path); } if (tempNode.left != null) { stack.push(tempNode.left); stack.push(path + "->" + tempNode.left.val); } if (tempNode.right != null) { stack.push(tempNode.right); stack.push(path + "->" + tempNode.right.val); } } return res; } }
class TreeNode { int val; TreeNode left; TreeNode right;
public TreeNode(){}; public TreeNode(int val){this.val = val;} public TreeNode(int val, TreeNode left, TreeNode right){ this.val = val; this.left = left; this.right = right; } }
class MyUtils {
public static TreeNode buildTree(Integer[] arr) { return buildTreeHelper(arr, 0); }
public static TreeNode buildTreeHelper(Integer[] arr, Integer index) { if (index >= arr.length || arr[index] == null) { return null; }
TreeNode node = new TreeNode(arr[index]);
node.left = buildTreeHelper(arr, 2 * index + 1); node.right = buildTreeHelper(arr, 2 * index + 2);
return node; } }
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总结